600=2x^2+x

Solution for 600=2x^2+x equation:

600=2x^2+x

We move all terms to the left:

600-(2x^2+x)=0

We get rid of parentheses

-2x^2-x+600=0

We add all the numbers together, and all the variables

-2x^2-1x+600=0

a = -2; b = -1; c = +600;
Δ = b2-4ac
Δ = -12-4·(-2)·600
Δ = 4801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{4801}}{2*-2}=\frac{1-\sqrt{4801}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{4801}}{2*-2}=\frac{1+\sqrt{4801}}{-4}
$